2304+x^2=5329

Solution for 2304+x^2=5329 equation:

2304+x^2=5329

We move all terms to the left:

2304+x^2-(5329)=0

We add all the numbers together, and all the variables

x^2-3025=0

a = 1; b = 0; c = -3025;
Δ = b2-4ac
Δ = 02-4·1·(-3025)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-110}{2*1}=\frac{-110}{2}
=-55
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+110}{2*1}=\frac{110}{2}
=55
$